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#15 | |
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Stop writing "vert", ffs!
Drives: 2011 2LT Convertible Join Date: Feb 2012
Location: Gambrills, MD
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The system has all the energy that it has regardless of how it’s distributed. In the case discussed above, making a number simplifying assumptions, a car hitting a wall at 120km/hr will experience the same kinetic energy transfer as if it hit another identical car also travelling at 120km/hr directly towards it. In the car/wall scenario 100% of the kinetic energy dissipation is carried by the car. In the car/car scenario, there is twice the energy in the system, but it is dissipated equally between the two cars. Again, this only holds if a lot of simplifying assumptions are made (e.g. no energy goes into heating the wall, both cars absolutely identical, no friction losses, etc….) This problem is a classic one that all physics students are introduced to; and many think that the 2-car scenario is somehow worse than the car vs wall because the relative velocity is twice as high.
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Vararam | Vmax Ported TB | Ported IM | Vmax Black ICE-olator |
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#16 |
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Retarded One-Legged Owl
Drives: 2010 Black Camaro 2SS Join Date: Oct 2008
Location: San Antonio, TX
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Hey, I'm a civil engineer too
![]() So, both of y'all are correct. But you're comparing apples to oranges. ![]() If two cars weigh 1,000kg and are travelling towards each other at 60 kph, then car A's speed will look like 120kph to the driver of car B. However, the formula for kinetic energy is: ![]() Notice how v is squared? That means that you can't simply add the velocities of two cars travelling 60kph and assume that a collision between the two would be the same as a single car going 120kph hitting an imovable object. Look at it this way, the two cars going 60kph would have a kinetic energy of: 60kph = 16.66 m/s 0.5(1000)(16.66^2) + 0.5(1000)(16.66^2) = 277,777.77 Joules The single car going 120kph would have a kinetic energy of: 120kph = 33.33 m/s 0.5(1000)(33.33^2) = 555,555.55 Joules So, yeah, hopefully seeing the math clears up some confusion
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#17 |
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Because I Can
Drives: 08 IOM G8GT 11 Victory Red SS Join Date: Jan 2010
Location: Sanford
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Ok its been a long time, but if we are going to state that two cars moving at 60 KMH collide in opposite directions is the same as hitting a stationary wall isn't this incorrect because.
1. An object in motion tends to stay in motion. So two cars colliding isn't going to completely stop either object like a wall. Energy will continue to travel through both cars causing more damage than only one car hitting a stationary wall. 2. Kinetic energy is dispersed completely? Kind of like, when you throw a basket ball against a wall it bounces back with X force, but if you throw two basketballs at each other you cause more energy to be dispersed and you get more of a reactionary effect. Im no expert, Im only trying to remember stuff I learned in school 20 years ago. If Im wrong, Im wrong. |
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#18 |
![]() Drives: 2011 Mustang GT Join Date: Mar 2011
Location: Fort Worth, TX
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Nope, no bolting into the ground needed. Again this shows how relative the speed is. Of course there are other factors that play into this that don't make them exactly the same but in the simplistic way to view things this is how it should be viewed.
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#19 |
![]() ![]() ![]() ![]() Drives: 2013 ZL1 Join Date: Mar 2010
Location: St. Joseph
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I have a phD in astrophysics, so I say you're all wrong and I'm right!!
![]() Seriously though, I appreciate people correcting my ignorance with facts, but one's qualifications have nothing to do with the merit of one's arguments. |
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#20 | |||
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Retarded One-Legged Owl
Drives: 2010 Black Camaro 2SS Join Date: Oct 2008
Location: San Antonio, TX
Posts: 9,745
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Losses due to heat transfer, losses due to parts coming off the car, losses due to wind drag, the list goes on and on. So, first you have to explain the most basic stripped-down version of the situation before you can attempt to dispute the real life circumstances. Quote:
![]() Quote:
![]() I should also point out that, Civil Engineers only have a very basic overview of the kind of engineering that goes into understanding crash physics.
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#21 | |
![]() Drives: 2011 Mustang GT Join Date: Mar 2011
Location: Fort Worth, TX
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#22 | |
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Moderator
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This is a good discussion.
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#23 | |
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Retarded One-Legged Owl
Drives: 2010 Black Camaro 2SS Join Date: Oct 2008
Location: San Antonio, TX
Posts: 9,745
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If a moving vehicle hits a parked car, the force felt will not be the same as if the vehicle hit an immovable wall. There will be a transfer of energy from the moving vehicle to the stationary vehicle. After the collision occurs, the moving vehicle will still be moving forward, just at a slower rate of speed. Therefore, it wouldn't be a 120-to-0 kph collision. It would be more like a 120-to-84.85 kph collision (Assuming 100% conservation of energy, which we both know is unlikely) ![]() Granted, the initial impact will be violent in both cases, and the human body would probably be incapable of determining the difference, since you'd probably be severely injured in both instances, but if you measured the collision with scientific equipment, the results would support my above calculations.
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#24 | |
![]() Drives: 2002 Dodge Ram :( Join Date: Aug 2011
Location: Nebraska
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Oh, btw, I must have been ill during that lecture on 1/2 mv^2. JK
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#25 | |
![]() Drives: 2011 Mustang GT Join Date: Mar 2011
Location: Fort Worth, TX
Posts: 168
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A car going 240kmph into a non moving car would create the same forces as 2 cars going at each other at 120kmph. Nothing about immovable walls. |
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#26 |
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Retarded One-Legged Owl
Drives: 2010 Black Camaro 2SS Join Date: Oct 2008
Location: San Antonio, TX
Posts: 9,745
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I think we're splitting hairs at this point
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